Tuesday, June 14, 2011

Autoluna 1:1 Secondary Text 2

By Lucian Green and Bradley Hunter
A chamber musician said he wanted to find a property of a packet of biscuits. He said he would do this by finding the surface area of a number of biscuits. He measured the width (X), the depth (Y), and the height (Z) of each biscuit. Surface area is found by multiplying the lengths of the sides, which are at right angles to each other. For example, the number of square centimetres in a square with width and height 2 cm, is two groups of two = 4 cm2. So, the total surface area is top area + bottom area + left area + right area + front area + back area = 2 x (top area + left area + front area) = 2 x ((X x Y) + (Y x Z) + (X x Z). For example, given X = 4 cm, Y = 2 cm and Z = 1 cm, the surface area = 2 x ((4 x 2) + (2 x 1) + (4 x 1) = 2 x (8 + 2 + 4) = 2 x (14) = 28 cm2. Then, he said that when the left hand side and the right hand side of the surface area formula equal each other, then the system is stable. In this way, he found the property of a packet of biscuits, which was the surface area of a number of biscuits.
A chamber violinist said he wanted to calculate the particular way a thought was thought of. He said he would do this by finding the rule for an example. He took the example of putting a shoe on a baby’s foot, which was part of dressing her. He said that he would decide to dress the baby before putting the shoe on her foot. He said that when it was true that a rule had been found for an example and it was true that an example had been found, then the system was stable. In this way, he calculated the particular way a thought was thought of by finding the rule for an example.
Another chamber musician calculated a way of working in a storage bay. She did this by covering up the storage bay so that there were no gaps. She did this by measuring the width and height of the opening of the storage bay. Then, she cut out a plastic rectangle with this width and height, and taped it to the opening of the storage bay. She said that when it was true that he had covered the storage bay and it was true that it had been necessary, then the system was stable. In this way, she calculated a way of working in the storage bay by covering it up.
Also, a chamber flutist calculated a way of navigating his room. He did this by computing a map of the parts of his room. Firstly, he wrote down a list of items in his room. Then, he found each of the items in his list. He said that when it was true that he had made a map of his room and it was true that it had been necessary, then the system was stable. In this way, he calculated a way of navigating his room by computing a map of it.
Then, a chamber musician tested that he spent his day doing each activity for the right amount of time. He did this by measuring the amount of time he lay in his bed, which was determined by the interval of time that he was in contact with the bed. He calculated this by testing whether the bed’s maximum height was equal to his minimum height, when he lay on it. Then, he said that when it was true that he spent the right amount of time in bed and it was true that it was necessary to do this, then the system was stable. In this way, he tested that he spent part of his day lying in his bed for the right amount of time.

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